posted by Mike .
A 75.0 mL volume of 0.200 M NH3 (Kb=1.8x10^-5) is titrated with 0.500 M HNO3. Calculate the pH after the addition of 28.0 mL of HNO3.
NH3 + HNO3 ==> NH4NO3
Set up an ICE chart, determine which reagent is in excess after the addition of the HNO3, the pH from that.