# Calc 2: Area under the curve

posted by .

Find the area of the region enclosed between y=2sin(x and y=3cos(x) from x=0 to x=0.4pi

Hint: Notice that this region consists of two parts.

Notice: I'm getting 1.73762 but apparently that is wrong.

• Calc 2: Area under the curve -

Find x where 2sin(x)=3cos(x) (div by cos)
2tan(x)=3
tan(x)=1.5
x=56.31degr
Area(from x=0 to x=56.31)=
(3sin(56.31)+2cos(56.31)-(3sin(0)+2cos(0))
=3.60555-2=1.60555
Area(from x=56.31 to x=72)=
(-2cos(72)-3sin(72))-(-2cos(56.31)-3sin(56.31))=-3.47120-(-3.60555)=0.13435
The total area=1.60555+0.13435=1.7399

## Similar Questions

1. ### Math- Calc

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. y=e^(4x), y=e^(6x), x=1
2. ### Calculus

Find the area of the region enclosed between y = 2sin (x) and y = 2cos (x) from x = 0 to x = pi/4. Thanks for your help :)
3. ### pre-calc

area of a rectangular region: a farmer wishes to create two rectangular regions bordering a river, by three fences perpendicular to the river and one connecting them. suppose that x represents the length of each of the three parallel …
4. ### Calculus

These are the two problems from my homework I don't get.. can you help me?
5. ### Calculus

1. Find the area of the region bounded by the curves and lines y=e^x sin e^x, x=0, y=0, and the curve's first positive intersection with the x-axis. 2. The area under the curve of y=1/x from x=a to x=5 is approximately 0.916 where …
6. ### Calculus

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Then find the area of the region. 2y = 4(x^(1/2)), y=4, and 2y +2x = 6 I keep getting an area around 21.3 but it is incorrect. Am I …
7. ### Math

A man owns a rectangular piece of land. The land is divided into four rectangular pieces, known as Region A, Region B, Region C, and Region D. One day his daughter, Nancy, asked him, what is the area of our land?
8. ### calculus

R is the first quadrant region enclosed by the x-axis, the curve y = 2x + b, and the line x = b, where b > 0. Find the value of b so that the area of the region R is 288 square units.
9. ### calculus

R is the first quadrant region enclosed by the x-axis, the curve y = 2x + a, and the line x = a, where a > 0. Find the value of a so that the area of the region R is 18 square units.
10. ### Calculus

Find the area of the region enclosed between y=4sin(x) and y=2cos(x) from x=0 to x=0.7pi. Hint: Notice that this region consists of two parts.

More Similar Questions