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Calc 2: Area under the curve

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Find the area of the region enclosed between y=2sin(x and y=3cos(x) from x=0 to x=0.4pi

Hint: Notice that this region consists of two parts.

Notice: I'm getting 1.73762 but apparently that is wrong.

  • Calc 2: Area under the curve -

    Find x where 2sin(x)=3cos(x) (div by cos)
    Area(from x=0 to x=56.31)=
    Area(from x=56.31 to x=72)=
    The total area=1.60555+0.13435=1.7399

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