Four candidates are running for president of the student council. three other candidates are running for vice-president. how many different ways can the two offices be filled?
We can cut a square diagonally in half to get two triangles. Suppose the
perimeter of the square is 3cm longer than the perimeter of a resulting triangle.
What is the perimeter of the square?
To find the number of different ways the two offices can be filled, we can use the concept of permutations.
For the president position, there are 4 candidates running. So, there are 4 possible choices for president.
For the vice-president position, there are 3 candidates running. So, there are 3 possible choices for vice-president.
Since these two positions are independent of each other, we can multiply the number of choices for president by the number of choices for vice-president to get the total number of ways:
Total number of ways = Number of choices for president × Number of choices for vice-president
= 4 × 3
= 12
Therefore, there are 12 different ways the two offices can be filled.
To determine the number of different ways the two offices can be filled, we need to multiply the number of choices for the president by the number of choices for the vice-president.
Given that there are four candidates running for president and three candidates running for vice-president, we can use the multiplication principle to find the total number of possibilities.
Number of choices for president = 4
Number of choices for vice-president = 3
To determine the total number of possibilities, we multiply these two numbers together:
Total number of possibilities = Number of choices for president * Number of choices for vice-president
Total number of possibilities = 4 * 3
Total number of possibilities = 12
Therefore, there are 12 different ways the two offices can be filled.