220 ml of an HCl solution that is 31.4% by mass is required to neutralize .50 gal of the chlorine solution. what is the molarity of the OH- of the clorine solution? chlorine solution is NaOCl in NaOH
To find the molarity of the OH- in the chlorine solution, we first need to find the moles of HCl in 220 ml of the HCl solution. Then, we can use the stoichiometry of the neutralization reaction between HCl and NaOH to determine the moles of NaOH in the chlorine solution. Finally, we divide the moles of NaOH by the volume of the solution in liters to obtain the molarity.
Step 1: Find moles of HCl.
To find the moles of HCl, we need the mass and molar mass of HCl. The mass of HCl can be calculated by multiplying the volume of the solution (220 ml) by its density, which can be assumed to be 1 g/ml since it is approximately the same as water. The molar mass of HCl is the sum of the atomic masses of hydrogen (H) and chlorine (Cl), which is 1 g/mol + 35.5 g/mol = 36.5 g/mol.
Mass of HCl = Volume of Solution × Density of Solution
Mass of HCl = 220 ml × 1 g/ml
Mass of HCl = 220 g
Moles of HCl = Mass of HCl / Molar Mass of HCl
Moles of HCl = 220 g / 36.5 g/mol
Step 2: Determine moles of NaOH.
The balanced equation for the neutralization reaction between HCl and NaOH is:
HCl + NaOH → NaCl + H2O
From the equation, we can see that the stoichiometric ratio between HCl and NaOH is 1:1. Therefore, the moles of NaOH will be equal to the moles of HCl.
Moles of NaOH = Moles of HCl
Step 3: Convert moles of NaOH to molarity.
The molarity (M) of a solution is defined as the moles of solute divided by the volume of the solution in liters (L).
Molarity (M) = Moles of NaOH / Volume of Solution (in L)
Since we are given the volume of the solution in gallons, we must convert it to liters. 1 gallon is approximately equal to 3.78541 liters.
Volume of Solution (in L) = 0.50 gal * 3.78541 L/gal
Now we can calculate the molarity of the OH- in the chlorine solution:
Molarity of OH- = Moles of NaOH / Volume of Solution (in L)