Name the lengths of the sides of three rectangles that have perimeters of 14 units.
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To find the lengths of the sides of three rectangles with perimeters of 14 units, we can use the formula for the perimeter of a rectangle, which is:
Perimeter = 2 * (length + width)
Let's solve for the lengths:
For the first rectangle, let's assume the length is 5 units. Substituting this into the formula, we have:
14 = 2 * (5 + width)
14 = 10 + 2 * width
4 = 2 * width
width = 2 units
So, the first rectangle has a length of 5 units and a width of 2 units.
For the second rectangle, let's assume the length is 4 units. Substituting this into the formula, we have:
14 = 2 * (4 + width)
14 = 8 + 2 * width
6 = 2 * width
width = 3 units
So, the second rectangle has a length of 4 units and a width of 3 units.
For the third rectangle, let's assume the length is 6 units. Substituting this into the formula, we have:
14 = 2 * (6 + width)
14 = 12 + 2 * width
2 = 2 * width
width = 1 unit
So, the third rectangle has a length of 6 units and a width of 1 unit.
To summarize, the three rectangles with perimeters of 14 units have the following side lengths:
- Rectangle 1: Length = 5 units, Width = 2 units
- Rectangle 2: Length = 4 units, Width = 3 units
- Rectangle 3: Length = 6 units, Width = 1 unit
Hi people in the out side world
fat stupid people who create websites
P = 2L + 2W
Some possible rectangles:
2 by 5
1 by 6
3 by 4