# Calculus

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Hey, we covered limits at the beginning of the year, but I cannot remember how to do them at all.
>>>what is the limit, as x approaches 2, of ((1/x )-(1/2))/(x-2)?

• Calculus -

f= (1/x-.5)/(x-2)

as x>>2, (1/2=1/2)/(2-2) so it is of the form 0/0, so use LHopitals rule

as x>>2= (-1/x^2)/(1)= -1/4 / 1= -1/4

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