An airplane rises vertically 1000 feet over a horizontal distance of 1 mile. What is the angle of elevation of the airplane's path? (hint: 1 mile = 5280 feet)

Solved under a previous post.

klj

To find the angle of elevation of the airplane's path, we can use basic trigonometry. The angle of elevation is equal to the opposite side over the adjacent side.

In this case, the opposite side is the vertical rise of 1000 feet, and the adjacent side is the horizontal distance of 1 mile (which is 5280 feet).

So, the angle of elevation can be found using the formula:
angle of elevation = arctan(opposite/adjacent)

angle of elevation = arctan(1000/5280)

Now, let's calculate the angle of elevation.

Using a calculator, we get:
angle of elevation ≈ 10.6 degrees

Therefore, the angle of elevation of the airplane's path is approximately 10.6 degrees.