# prep chem

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How many milliliters of oxygen 2(g) will be produced at 720mmHg and 17 celsius if 0.460 grams of KClO3 are reacted in the reaction?

Formula is
2 KClO3 --> 2 KCl + 3 O2(g)

I know to change temp into K

• prep chem -

moles O2= 3/2 molesKCLO3= 3/2 (.460/molmass)

volume=nRT/Pressue

make certain you use the correct R (mmHg, liters, K)

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