An aspirin tablet weighing 0.475 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved
the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. Exactly 3.00 mL
of the solution was pipetted into a 100 mL volumetric flask and diluted to the mark with FeCl3 solution.
The concentration of the diluted solution is???
ive tried it a couple times but i cant figure it out....
You mustn't let these problems confuse you. Stick to what is going on and don't get distracted.
0.475 g of 68.2% ASA==> 250 mL.
Then 3.00 ==> 100 mL.
0.475 x 0.682 x (1 mol/180.18) = ?? moles ASA placed in the 250 mL volumetric flask; therefore, the concn of ASA in that 250 mL flask is just ?? moles/0.250 mL = xxM ASA. Right?
Then we take 3.00 mL and dilute it to 100; therefore, the concn in the 100 mL flask is
xxM x (3.00/100) = zzM.
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To find the concentration of the diluted solution, we need to determine the number of moles of ASA (acetylsalicylic acid) in the aspirin tablet and calculate the concentration of the diluted solution using the volume of the solution and the number of moles.
1. First, we need to find the number of moles of ASA in the tablet. We can use the mass percentage and the molar mass of ASA.
Mass of ASA in the tablet = Mass of tablet × Percentage of ASA
Mass of ASA in the tablet = 0.475 g × 0.682 = 0.32335 g
Number of moles of ASA = Mass of ASA / Molar mass of ASA
Number of moles of ASA = 0.32335 g / 180.16 g/mol = 0.0017952 mol
2. Next, we need to calculate the concentration of the diluted solution. We can use the volume of the solution and the number of moles of ASA.
Volume of the diluted solution = 100 mL = 0.1 L (since 1 mL = 0.001 L)
Volume of the solution pipetted out = 3.00 mL = 0.003 L (since 1 mL = 0.001 L)
Number of moles of ASA in the diluted solution = Number of moles of ASA in the tablet × (Volume of the solution pipetted out / Volume of the diluted solution)
Number of moles of ASA in the diluted solution = 0.0017952 mol × (0.003 L / 0.1 L) = 0.000053856 mol
Concentration of the diluted solution = Number of moles of ASA in the diluted solution / Volume of the diluted solution
Concentration of the diluted solution = 0.000053856 mol / 0.1 L = 0.00053856 mol/L
Therefore, the concentration of the diluted solution is 0.00053856 mol/L.