Compound A reacts with element B (a halogen) to form compounds C and D as the only products. When 2.000 grams of B react with an excess of sodium metal 2.363 grams of the sodium halide are formed. Compound A is a volatile liquid at room temperature with a density of 0.8800g/ml. It contains only carban and hydrogen, and for every 1.000 gram of hydrogen it contains 11.89 grams of carbon. At 100C and 800.0 torr it is a gas with a vapor density of 2.685 g/L. Compound D is the hydrogen, and the rest element
B.
1.)Identify A,B,C,and D. Write a balanced equation for the reaction.
Some hints.
1. B is a halogen.
Na + B ==> NaB
You know NaB is 2.636 g and B is 2.00 g. Calculate the atomic mass B and identify it.
Use P*molar mass = density*R*T to identify the molar mass of A. Then use the 11.89 and 1 g to find the empirical formula. Those two will tell you the molecular formula.
To identify the compounds A, B, C, and D, and write a balanced equation for the reaction, we need to analyze the given information. Let's break it down step by step:
1. Compound A is a volatile liquid at room temperature with a density of 0.8800 g/ml. It contains only carbon and hydrogen, and for every 1.000 gram of hydrogen, it contains 11.89 grams of carbon.
Considering the information given, the compound A is likely a hydrocarbon. The ratio of carbon to hydrogen suggests that the hydrocarbon is C11H(n), where "n" is the number of hydrogen atoms.
2. At 100°C and 800.0 torr, compound A is a gas with a vapor density of 2.685 g/L.
Vapor density can be used to determine the molar mass of a gas. The vapor density of compound A, 2.685 g/L, tells us that the molar mass of compound A is 2.685 g/mol.
3. Compound B is a halogen, and it reacts with compound A to form compounds C and D as the only products.
Given that compound B is a halogen, it could be chlorine (Cl2), bromine (Br2), iodine (I2), or fluorine (F2). However, we don't have enough information to determine which specific halogen it is.
4. When 2.000 grams of B react with an excess of sodium metal, 2.363 grams of the sodium halide are formed.
This information suggests that compound B reacts with sodium (Na) to form a sodium halide. The balanced equation for this reaction can be written as follows:
2B + 2Na -> Na2B2
Based on this equation, the molar mass of compound B can be calculated using the mass of sodium halide formed.
5. Compound D is the hydrogen, and the rest is element B.
Compound D is simply hydrogen (H), and the rest of the element in compound B is the halogen, B.
In summary:
- Compound A: A hydrocarbon, likely C11H(n).
- Compound B: A halogen, but the specific halogen (Cl2, Br2, I2, or F2) cannot be determined with the given information.
- Compound C: Not specified.
- Compound D: Hydrogen (H).
- Balanced equation: 2B + 2Na -> Na2B2