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f(x,y)= 10x^1/3 y^2/3

Compute (27,64)

so 10(27)^1/3 * (64)^2/3

10 * (27)^1/3 * (64)^2/3

I know that the answer is 480 but I am having a hard time calculating 27^1/3 and 64^2/3.

cube root of 27? 3
cube root of 64, then squared?
64=4*4*4 so the answer is 16

10*3*16=...

Oh, I see. Thank you

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