According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution? Assume that there is excess FeCl2.
FeCl2(aq) + 2 LiOH(aq) → Fe(OH)2(s) + 2 LiCl(aq)
The number of moles of Fe(OH)2 that can form is equal to the number of moles of LiOH present in the solution. Since the solution is 0.227 M LiOH, the number of moles of LiOH present is 0.227 moles/L x 175.0 mL = 39.675 moles. Therefore, 39.675 moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution.
To determine the number of moles of Fe(OH)2 that can form from the given solution, you need to use the concepts of stoichiometry and the concentration of the LiOH solution.
First, you should convert the volume of the LiOH solution from milliliters (mL) to liters (L) to match the unit of concentration (Molarity, M). Remember that 1 L = 1000 mL.
Given:
Volume of LiOH solution = 175.0 mL = 175.0 mL x (1 L / 1000 mL) = 0.175 L
Concentration of LiOH solution = 0.227 M
Next, use the balanced chemical equation to determine the stoichiometric ratio between Fe(OH)2 and LiOH. According to the equation, for every 2 moles of LiOH, 1 mole of Fe(OH)2 is produced.
Now, calculate the moles of LiOH in the solution:
Moles of LiOH = concentration (M) x volume (L)
Moles of LiOH = 0.227 M x 0.175 L = 0.039725 moles (rounded to 4 decimal places)
Since the stoichiometry of the reaction indicates that 2 moles of LiOH are required to produce 1 mole of Fe(OH)2, you can conclude that you can form half as many moles of Fe(OH)2 as the moles of LiOH used.
Moles of Fe(OH)2 = 0.039725 moles x (1/2) = 0.019863 moles (rounded to 6 decimal places)
Therefore, approximately 0.019863 moles of Fe(OH)2 can form from 175.0 mL of 0.227 M LiOH solution, assuming there is excess FeCl2.
To determine the number of moles of Fe(OH)2 that can form from 175.0 mL of 0.227 M LiOH solution, you will need to use the concept of stoichiometry.
First, calculate the number of moles of LiOH in the given solution:
Moles of LiOH = Volume (in liters) × Molarity
Moles of LiOH = 0.175 L × 0.227 mol/L
Next, use the coefficients from the balanced equation to determine the moles of Fe(OH)2 that can form:
According to the balanced equation, the ratio of LiOH to Fe(OH)2 is 2:1. This means that for every 2 moles of LiOH, 1 mole of Fe(OH)2 will be formed.
Number of moles of Fe(OH)2 = (Moles of LiOH) / 2
Substituting the value of moles of LiOH into the equation:
Number of moles of Fe(OH)2 = (0.175 L × 0.227 mol/L) / 2
Calculate this expression to find the number of moles of Fe(OH)2 that can form from the given solution.