What is the molarity (mol/L) of sodium (Na) in a solution containing 0.4 mole ofNa + cation in
400 mL of an aqueous (water) solution?
recall that molarity is just moles of solute per liter of solution, or
M = n / V
first we convert the 400 mL to L:
400 mL = 0.4 L
substituting,
M = 0.4 / 0.4
M = 1 M
hope this helps~ :)