f a water bed is 1.81 m on each vertical side and 30 cm high. Find its weight. The acceleration of gravity is 9.8 m/s2 and the density of water is 1000 kg/m3. Answer in units of N
I assume you mean each horizontal side.
Weight= volume*density*g
= 1.81*2 * .3 * 1000*9.8 N
To find the weight of the water bed, we need to calculate the force exerted by the water on the bed due to its weight.
First, we need to determine the volume of water in the water bed. The volume can be found by multiplying the dimensions of the water bed: length × width × height.
Given:
Length = 1.81 m
Width = 1.81 m
Height = 30 cm = 0.3 m
Density of water = 1000 kg/m^3
Volume = Length × Width × Height
Volume = 1.81 m × 1.81 m × 0.3 m
Volume = 0.98227 m^3 (rounded to 5 decimal places)
Now, we can calculate the weight of the water in the bed by multiplying the volume by the density of water and the acceleration due to gravity.
Weight = Volume × Density × acceleration due to gravity
Weight = 0.98227 m^3 × 1000 kg/m^3 × 9.8 m/s^2
Weight = 9598.366 N (rounded to 3 decimal places)
Therefore, the weight of the water bed is approximately 9598.366 N.