Fill in the blanks:
For all sets A and B, if A is in the set of B, then A union B in in the set of B.
Proof: Suppose A and B are any sets and A in in the set of B. [we must show that __________] Let x be and element of _______. [we must show that __________] by definition of union, x is an elment of ______ ______ x is an element of _______. In case x is an element of ________, then since A is in the set of B, x is an element of _________. In case x is an element of B, then clearly, x is an element of B. So in either case, x is an element of __________ [as was to be shown]
Proof: Suppose A and B are any sets and A in in the set of B. [we must show that A∪B ⊆B]
Let x be an element of A∪B. [we must show that x∈A or x∈B] By definition of union, x is an elment of ______ or x is an element of _______.
In case x is an element of ________, then since A is in the set of B, x is an element of _________.
In case x is an element of B, then clearly, x is an element of B.
So in either case, x is an element of __________ [as was to be shown]
Hope the above hints are enough for you to complete the proof.
Proof: Suppose A and B are any sets and A is in the set of B. We must show that A union B is in the set of B.
Let x be an element of A union B. We must show that x is an element of the set of B.
By definition of union, if x is an element of A union B, then x is either an element of A or x is an element of B.
In case x is an element of A, then since A is in the set of B, x is an element of the set of B.
In case x is an element of B, then clearly x is an element of B.
So in either case, x is an element of the set of B. This completes the proof.
Therefore, for all sets A and B, if A is in the set of B, then A union B is in the set of B (as was to be shown).