Zn + HCl --> ZnCl2 + H2
If 18 grams of Zn are used in the following reaction, how many grams of H2 will be produced?
first let's see if the chemical equation is balanced.
Zn + HCl --> ZnCl2 + H2
since not yet balanced, then we balance it :P
Zn + 2HCl --> ZnCl2 + H2
since we are given grams of Zinc, we need to find the mass of Zn from periodic table to convert it to moles. thus
Zn = 65.4 g/mol
also since we are required to find grams of H2, we look also for the mass of H:
H = 1 , thus
H2 = 1*2 = 2 g/mol
therefore,
18 g Zn * (1 mol Zn / 65.4 g Zn) * (1 mol H2 / 1 mol Zn) * (2 g H2 / 1 mol H2) = 0.55 g H2
hope this helps~ :)
To determine the number of grams of H2 produced, we need to use stoichiometry.
Step 1: Write the balanced chemical equation:
Zn + 2HCl --> ZnCl2 + H2
Step 2: Find the molar mass of Zn:
The molar mass of Zn is 65.38 g/mol.
Step 3: Convert the given mass of Zn to moles:
18 g Zn × (1 mol Zn / 65.38 g Zn) = 0.275 mol Zn
Step 4: Use the stoichiometry ratio to find the moles of H2:
From the balanced equation, we see that the ratio of Zn to H2 is 1:1. Therefore, the moles of H2 produced will be the same as the moles of Zn used, which is 0.275 mol.
Step 5: Convert the moles of H2 to grams:
The molar mass of H2 is 2.02 g/mol.
0.275 mol H2 × (2.02 g H2 / 1 mol H2) = 0.5565 g H2
Therefore, if 18 grams of Zn are used in the reaction, approximately 0.5565 grams of H2 will be produced.