Mr. Ranier's car uses about 1.6 fluid ounces of gas per minute when the engine is idling. One night, he parked his car but forgot to turn off the motor. He had just filled his tank. His tank holds 12 gallons. About how many hours will it take before his car runs out of gas?
1 gallon = 128 ounces
12 * 128 = 1,536 ounces
1,536 / 1.6 = 960 minutes
960/60 = 16 hours
To determine how many hours it will take for Mr. Ranier's car to run out of gas, we need to know the gas consumption rate in fluid ounces per hour. Since we know that the car uses about 1.6 fluid ounces of gas per minute, we can convert this rate to fluid ounces per hour.
To convert from minutes to hours, we divide the current rate by 60 (since there are 60 minutes in an hour). Therefore, the gas consumption rate in fluid ounces per hour is:
1.6 fluid ounces/minute * (1 hour / 60 minutes) = 0.0267 fluid ounces/hour.
Now that we know the rate at which the car consumes fuel in fluid ounces per hour, we can determine the total fuel capacity of the tank in fluid ounces. Since the tank holds 12 gallons and there are 128 fluid ounces in a gallon, we can calculate the total fuel capacity in fluid ounces:
12 gallons * 128 fluid ounces/gallon = 1536 fluid ounces.
Next, we can divide the total fuel capacity in fluid ounces by the gas consumption rate to find the number of hours the car can run before running out of gas:
1536 fluid ounces / 0.0267 fluid ounces/hour = 57590.14 hours.
Therefore, it will take approximately 57590.14 hours for Mr. Ranier's car to run out of gas if he forgets to turn off the engine.