factor each of the following:

a)x^2+10x+25
b)x^2+16x+28
c)x^2-9x+14

x^2+10x+25=(x+5)*(x-5)

Becouse:

(x+5)*(x-5)=x*x+5*x-5*x-25=x^2+5x-5x+25=x^2+25

x^2+16x+28=(x+2)*(x+14)

Becouse:

(x+2)*(x+14)=x*x+2*x+14x+28=x^2+2x+14x+28=x^2+16x+28

x^2-9x+14=(x-7)*(x-2)

Becouse:

(x-7)*(x-2)=x*x-7x-2x+2*7=x^2-9x+14

i don't realy get it still like i do get it but at the same time i don't :( sorry im being an thik head lol

To factor each of the given quadratic expressions, we need to find two binomial expressions that, when multiplied, give us the quadratic expression. The binomial expressions will have the form (x + a) and (x + b), where a and b are constant terms.

a) To factor the expression x^2 + 10x + 25:
We want to find two numbers whose sum is 10 and whose product is 25. These numbers are 5 and 5. So, we can rewrite the expression as:
x^2 + 5x + 5x + 25
Grouping terms, we have:
(x^2 + 5x) + (5x + 25)
Taking out the common factors, we get:
x(x + 5) + 5(x + 5)
Now, we can see that both terms have a common factor of (x + 5), so we can factor that out:
(x + 5)(x + 5)
Simplifying, we get:
(x + 5)^2

Therefore, the factored form of x^2 + 10x + 25 is (x + 5)(x + 5) or (x + 5)^2.

b) To factor the expression x^2 + 16x + 28:
We want to find two numbers whose sum is 16 and whose product is 28. These numbers are 4 and 14. So, we can rewrite the expression as:
x^2 + 4x + 14x + 28
Grouping terms, we have:
(x^2 + 4x) + (14x + 28)
Taking out the common factors, we get:
x(x + 4) + 14(x + 4)
Now, we can see that both terms have a common factor of (x + 4), so we can factor that out:
(x + 4)(x + 14)

Therefore, the factored form of x^2 + 16x + 28 is (x + 4)(x + 14).

c) To factor the expression x^2 - 9x + 14:
We want to find two numbers whose sum is -9 and whose product is 14. These numbers are -2 and -7. So, we can rewrite the expression as:
x^2 - 2x - 7x + 14
Grouping terms, we have:
(x^2 - 2x) + (-7x + 14)
Taking out the common factors, we get:
x(x - 2) - 7(x - 2)
Now, we can see that both terms have a common factor of (x - 2), so we can factor that out:
(x - 2)(x - 7)

Therefore, the factored form of x^2 - 9x + 14 is (x - 2)(x - 7).