How much surface area would 1 fluid oz. of gold cover?
Thickness .0002 (two Tenths)
1 US fluid ounce = 29.5735296 milliliters
area*thickness=29.573 cm^3
I am not certain of your unit for thickness, but at any rate, solve for area in cm^2
To calculate the surface area that 1 fluid ounce (oz.) of gold would cover, we first need to convert the thickness measurement from inches to a unit that matches the unit of surface area (square inches).
Given that the thickness is 0.0002 inches, we can proceed with the calculation.
The formula to calculate surface area is:
Surface Area = Volume / Thickness
To find the volume, we need to convert the fluid ounce measurement to cubic inches because the density of the gold is given in mass per unit volume (g/cm³ or g/ml), and we need to match the units.
1 fluid ounce ≈ 1.80469 cubic inches
Next, we can apply the formula:
Surface Area = 1.80469 cubic inches / 0.0002 inches
Surface Area ≈ 9,023.45 square inches
Therefore, 1 fluid ounce of gold, with a thickness of 0.0002 inches, would cover approximately 9,023.45 square inches of surface area.