posted by Leanna

I don't know how to do the integral of e^(lnx^2)dx and the integral of (sin sqrtx)/(sqrtx) dx

  1. MathMate

    1. ∫e^(lnx^2)dx
    use the identity e^(ln(y)) = y to simplify the expression.
    2. try the substitution u=sqrt(x).

  2. Leanna

    Thanks for help on 1.

    on 2. if i do u=sqrt(x) my du is 1/2x^(-1/2) and that means my du is in the denominator. So it would read 2integral of sin(u)/du

  3. bobpursley

    Nope, not on two.

    You cant solve it that way easily.

    This is difficult. Brake the sin function into its series equivalent, and integrate the series.

  4. bobpursley

    forget that last answer. I am tired.

  5. MathMate

    For 2, almost, but not quite!
    Start with:
    du = (1/2)dx/√x
    dx/√x = 2du
    ∫sin(√x) dx/√x

Respond to this Question

First Name

Your Answer

Similar Questions

  1. Calculus

    I don't know if I did these problems correctly. Can you check them?
  2. Calculus

    Find the volume of the solid whose base is the region in the xy-plane bounded by the given curves and whose cross-sections perpendicular to the x-axis are (a) squares, (b) semicircles, and (c) equilateral triangles. for y=x^2, x=0, …
  3. calculus

    how do you determine the convergence of : definite integral from 1--> infinity of lnx/(x^3)?
  4. Calculus Part 2

    y = tan(sqrtx) Find dy/dx. So I found it and I got the answer as sec^2(sqrtx) but the answer is (sec^2(sqrtx))/2(sqrtx)...why?
  5. Calculus

    lim(x->infinity) sqrtx sin(1/sqrtx) Someone please start me off. I don't know how to find the limits of trigonometric functions.
  6. Calculus

    I have two questions, because I'm preparing for a math test on monday. 1. Use the fundamental theorem of calculus to find the derivative: (d/dt) the integral over [0, cos t] of (3/5-(u^2))du I have a feeling I will be able to find …
  7. calc

    find integral using table of integrals ) integral sin^4xdx this the formula i used integral sin^n xdx =-1/n sin^n-1xcosx +n-1/n integral sin^n-2 using the formula this is what i got: integral sin^4xdx=-1/4sin^3xcosx+3/4 integral sin^2xdx= …
  8. Applied Calc

    Find the indefinite integral of (1-sqrtx)/(1+sqrtx)dx I just worked completely through this problem using substitution (u=1+sqrtx) and came to the answer 3+4sqrtx+x+C. This is incorrect. Not sure where I messed up.
  9. Calculus Math

    Find the height of y=((sqrtx)(3-x))/3 for 0<=x<=3 Use the arc length formula and note that 1/4x+1/2+x/4=(1/(2sqrtx) + sqrtx/x)^2 is a perfect suare.
  10. Math

    Evaluate the integral of 1/(1+sqrtx)^4 from [0,1] I started off letting u=1+sqrtx and du=1/2sqrtx, but then there is no 1/2sqrtx in the equation. What am I suppose to do next?

More Similar Questions