A heater caused the temperature of a 550 g Aluminum block to change from 22 degrees C to 145 degrees C. How many calories were required to heat the metal block?

q = mass x specific heat x (Trinal-Tinitial)

q = 550 x specific heat Al x (145-22)
Look up the specific heat Al in your text or notes and punch the calculator.

To find the amount of calories required to heat the aluminum block, we can use the formula:

Q = mcΔT

Where:
Q = amount of heat energy in calories
m = mass of the aluminum block in grams
c = specific heat capacity of aluminum in calories/gram °C
ΔT = change in temperature in °C

Let's break down the calculation step by step:

1. Convert the mass from grams to kilograms:
Mass of aluminum block = 550 g = 0.55 kg

2. Look up the specific heat capacity of aluminum:
The specific heat capacity of aluminum is approximately 0.897 calories/gram °C

3. Calculate the change in temperature:
ΔT = Final temperature - Initial temperature = 145 °C - 22 °C = 123 °C

4. Substitute the values into the formula:
Q = (0.55 kg) x (0.897 cal/g°C) x (123°C)

5. Calculate the product:
Q ≈ 74.571 calories

Therefore, approximately 74.571 calories were required to heat the aluminum block.