Harry planned a rectangular garden that was 40 feet long and 10 feet wide

Question

Harry planned a rectangular garden that was 40 feet long and 10 feet wide

1.What was the perimeter,in feet,of the garden that Harry planned?
2.What was the area,in square feet,of the garden that Harry planned?
3.Suppose Harry decided to change the shape of his garden to a square with the same area as the rectangle.What would be the perimeter,in feet,of the square garden?
SHOW AND EXPLAIN HOW U GOT THE ANSWERS!!!!

Answer 1

P = 2L + 2W

A = L * W

I'll be glad to check your answers.

Answer 2

HOW U GOT THE ANSWER

Answer 3

Perimeter = 2 times length + 2 times width

P = 2L + 2W
P = (2 * 40) + (2 * 10)
P = 80 + 20
P = ?

Answer 4

THXZ B & C

Answer 5

please i need help asap what is b and c

Answer 6

2.

Area = Length * Width

I'll be glad to check your answers.

Answer 7

400 square feet

Answer 8

80 ft. because a square must be equal on all sides, otherwise it’s a rectangle. Each side must be 20 ft. because the square root of 400 is 20 (what times itself equals 400, 20 x 20). If each side is 20, and there are 4 sides, do 20 x 4 for an answer. That's the explanation.

Harry planned a rectangular garden that was 40 feet long and 10 feet wide

P = 2L + 2W

HOW U GOT THE ANSWER

EXPLAIN

Perimeter = 2 times length + 2 times width

THXZ B & C

please i need help asap what is b and c

2.

400 square feet

Right.

80 ft. because a square must be equal on all sides, otherwise it’s a rectangle. Each side must be 20 ft. because the square root of 400 is 20 (what times itself equals 400, 20 x 20). If each side is 20, and there are 4 sides, do 20 x 4 for an answer. That's the explanation.