Maths
posted by chris .
Solve the initial value problem
(dy/dt)+2y=15 sin(t)+15 cos(t)
with y(0)=3

Maths 
Writeacher
chris or lisa or whoever 
To quote one of our very good math and science tutors: “You will find here at Jiskha that long series of questions, posted with no evidence of effort or thought by the person posting, will not be answered. We will gladly respond to your future questions in which your thoughts are included.”
Respond to this Question
Similar Questions

tigonometry
expres the following as sums and differences of sines or cosines cos8t * sin2t sin(a+b) = sin(a)cos(b) + cos(a)sin(b) replacing by by b and using that cos(b)= cos(b) sin(b)= sin(b) gives: sin(ab) = sin(a)cos(b)  cos(a)sin(b) … 
algebra
Can someone please help me do this problem? 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 … 
Math/Calculus
Solve the initialvalue problem. Am I using the wrong value for beta here, 2sqrt(2) or am I making a mistake somewhere else? 
TRIG!
Posted by hayden on Monday, February 23, 2009 at 4:05pm. sin^6 x + cos^6 x=1  (3/4)sin^2 2x work on one side only! Responses Trig please help!  Reiny, Monday, February 23, 2009 at 4:27pm LS looks like the sum of cubes sin^6 x + cos^6 … 
Precal
I do not understand how to do this problem ((sin^3 A + cos^3 A)/(sin A + cos A) ) = 1  sin A cos A note that all the trig terms are closed right after there A's example sin A cos A = sin (A) cos (A) I wrote it out like this 0 =  … 
Maths
Solve the initial value problem (dx/dt)+2x=cos(2t) with x(0)=5 
maths
Choose the option that gives the solution of the initialvalue problem dy dx=(1 + 2 cos2x^2)/y (y > 0), y= 1 when x = 0. Options A y = 1+ 2sin^2 x B y = (1 + 2 sin x)^2 C y = (4x + cos(2x))^2 D y = 4x + cos^2 x E y =sqrt(4x + cos(2x) … 
Trigonometry
Solve the equation for solutions in the interval 0<=theta<2pi Problem 1. 3cot^24csc=1 My attempt: 3(cos^2/sin^2)4/sin=1 3(cos^2/sin^2)  4sin/sin^2 = 1 3cos^2 4sin =sin^2 3cos^2(1cos^2) =4sin 4cos^2 1 =4sin Cos^2  sin=1/4 … 
Maths
Please solve this trigonometric identity proof problem. I have completed 20; this is the hardest one. Many thanks (sin^3(x)cos^3(x))/sin(x)cos(x)=1+sin(x)cos(x)