what is the vertex for the equation y = x2 – 4 and how did do find the answer
y=ax^2+bx+c
The axis of symmetry is the line x= -b/2a
In your equation y=x^2–4
a=1 b=0 c=-4
x= -b/2a=-(-0)/(2*1)=0/2=0
x=0
is the vertex for the equation y=x^2–4