trig

posted by .

3sin(2x)-2cos(x)=0

  • trig -

    Use the equation
    sin(2x) = 2 sin x cos x
    so that
    6 sinx cosx -2 cosx = 0
    cosx*(1 - 3sinx) = 0
    (I divided out -2)

    So the equation is satisfied wherever cosx = 0 or sinx = 1/3

    x = pi/2 and 0.3398 radians are two solutions. There are others in other quadrants.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Math - Trig Substitution

    How can I solve the integral of x^3√(9-x^2) dx using trigonometric substitution?
  2. Calculus

    Find the derivative of y with respect to x: y=3sin^4(2-x)^-1 y=[3sin(2-x)^-1]^4 y'=4[3sin(2-x)^-1]^3 (-3cos(2-x)^-1)(-1) -(2-x)^-2 y'=[12cos(2-x)^-1][3sin^3(2-x)^-1][2-x]^2 but the answer does not have a 3 in front of sin. What happened …
  3. trig

    finding the equivalent polar equation 2x+3y=6 I got r=6/2cos(theta)-3sin(theta) can anyone check plz
  4. Calc

    How do you know what shape the graph in the xy-plane represented by x=3sin(t) and y=2cos(t) is?
  5. Math

    Can you help me with this? I did this many times and got different answers each time. Find f. f ''(x) = 3e^x + 3sin(x) f(0) = 0 f(π) = 0 My work: f ''(x) = 3e^x + 3sin(t) f'(x) = 3e^x - 3cos(t) + C f(x) = 3e^x -3sin(t) + Cx +
  6. trig

    Find minimum value of 2cos x + 2cos y
  7. trig

    Find minimum value of 2cos x + 2cos y
  8. trig

    Find minimum value of 2cos x + 2cos y
  9. trigonometry

    Find all solutions on the interval [0.2pi) A) -3sin(t)=15cos(t)sin(t) I have no clue... b) 8cos^2(t)=3-2cos(t) All i did was move around the equation to make an quadratic for B. so -8cos^2(t)-2cos(t)+3 = 0
  10. Mathematics

    Given that 2cos^2 x - 3sin x -3 = 0, show that 2sin^2 x + 3sin x +1 = 0?

More Similar Questions