Earl N. Meyer found that it took 25.46mL of the 0.0100 M NaOH to reach the firtst equivalence point for the titration of 25.00mL of Zlot cola. What is the molar concentration of phosphoric acid in Zlot cola?
To find the molar concentration of phosphoric acid in Zlot cola, we can set up a balanced equation for the titration reaction. In this case, phosphoric acid (H₃PO₄) reacts with sodium hydroxide (NaOH) in a 1:1 ratio:
H₃PO₄ + NaOH → NaH₂PO₄ + H₂O
First, let's calculate the number of moles of NaOH used in the titration:
moles of NaOH = volume of NaOH (in L) × molar concentration of NaOH
Given that the volume of NaOH used is 25.46 mL, we need to convert it to liters by dividing by 1000:
volume of NaOH = 25.46 mL ÷ 1000 → 0.02546 L
The molar concentration of NaOH is given as 0.0100 M, so we can substitute the values into the formula to calculate the moles of NaOH:
moles of NaOH = 0.02546 L × 0.0100 mol/L
Next, using the balanced equation, we can determine the moles of phosphoric acid (H₃PO₄) based on the moles of NaOH used. Since the ratio between NaOH and H₃PO₄ is 1:1, the moles of H₃PO₄ will be the same as the moles of NaOH:
moles of H₃PO₄ = moles of NaOH
Finally, to find the molar concentration of phosphoric acid (H₃PO₄) in Zlot cola, we need to divide the moles of H₃PO₄ by the volume of Zlot cola:
molar concentration of H₃PO₄ = moles of H₃PO₄ / volume of Zlot cola (in L)
Given that the volume of Zlot cola used is 25.00 mL, we need to convert it to liters by dividing by 1000:
volume of Zlot cola = 25.00 mL ÷ 1000 → 0.02500 L
Substituting the values, we can calculate the molar concentration of H₃PO₄ in Zlot cola:
molar concentration of H₃PO₄ = moles of H₃PO₄ / 0.02500 L
By following these steps and plugging in the appropriate values, you can determine the molar concentration of phosphoric acid in Zlot cola.
H3PO4 + NaOH ==> NaH2PO4 + H2O
moles NaOH = M x L = ??
moles H3PO4 = 1:1; therefore, = same as moles NaOH.
M H3PO4 = moles H3PO4/L H3PO4.