chemistry

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A 828 mL sample of NO2 gas is at STP. If the volume changes to 598 mL and the temperature changes to 12ºC, what will be the new pressure in atmospheres?

new pressure=_____atm

  • chemistry -

    assuming the gas is ideal, we can use the formula,
    P1*V1/T1 = P2*V2/T2
    where
    P1 = initial pressure
    V1 = initial volume
    T1 = initial temperature (in K)
    P2 = final pressure
    V2 = final volume
    T2 = final temperature (in K)
    we first convert the given temp to Kelvin units:
    T2 = 12 + 273.15 = 285.15 K
    *then note that at STP, temp is at 273.15 K and 1 atm. substituting,
    P1*V1/T1 = P2*V2/T2
    (1)(828) / 273.15 = (P2)(598) / 285.15
    P2 = (828)(285.15) / (273.15)(598)
    P2 = 1.45 atm

    hope this helps~ :)

  • chemistry -

    thank you very much it does help a lot but when im doing this problems on my oown they dnt make any sense ..

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