Physics
posted by Wendy A. .
An 8.5 x 10^2 elevator is pulled up at a constant velocity of 1 m/s by a 10 kW motor. Calculate the efficiency of the motor.

power in work= mgh/t=8.5E2*9.8*1m/s=about 5000 watts
Efficiencey appx= 5000/10K aboaut 50 percent.
check that. 
You have to provide dimensions along with the 850 for the elevator.
M g V is the power delivered.
Divide that by 10,000 W for the efficiency 
Ok thanks to both for the answers!
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