# Physics

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The Hubble Space Telescope orbits the Earth at an approximate altitude of 612 km. Its mass is 11,100 kg and the mass of the Earth is 5.97×1024 kg. The Earth's average radius is 6.38×106 m. What is the magnitude of the gravitational force that the Earth exerts on the Hubble?

• Physics -

The Earth's radius is 6380 km .

F = Msat*Mearth*G/Rsat^2

= Msat* g * (Rearth/R)^2

Rsat = Rearth + 612 km = 6992 km
Re/R = 0.9125

g = 9.81 m/s^2

Hubble's weight in that orbit is
(0.9125)^2 = 83.3% of its weight on the Earth's surface.

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