math algebra help please!
posted by Steph .
12 points lie on a circumference of a circle how many inscribed triangles can be constructed having 3 vertices?
Respond to this Question
Similar Questions

Math: Combinations
There are 20 points all in one straight line and 15 others in a parallel line. How many possible triangles having these points as vertices can be formed? 
math
x^2 + y^2  8x 2y 3 = 0 the points S and T lie on the circumference of the circle. M is the midpoint of the chord ST. Length of Centre C to M is 2. whats the length of ST? 
geometry
m<S=30, m(arc)RS=84,and RU is tangent to the circle at R find m<U. It's a circle with a triangle inscribed, only the s and r lie on the circle and u extends past circle. can someone help i do not know or understand these problems … 
geometry
distint points a, b, c, d, e, and f are marked on a circle. How many triangles can be formed using these points as vertices? 
math
A circle of area 25 pi is graphed in the coordinate plane. If its center has coordinates (8,0), which of the following points MUST lie on the circumference of the circle? 
geometry
which of the following is a step in constructing an inscribed square using technology? 
Math
Six points lie on the circumference of a circle. How many different triangles can be drawn having some of these points as vertices? 
math
A circle is inscribed in triangle ABC with sides a, b, c. Tangents to the circle parallel to the sides of the triangle are constructed. Each of these tangents cuts off a triangle from ∆ABC. In each of these triangles, a circle … 
8th Grade PreAlgebra
Triangle PQR is transformed to triangle P'Q'R'. Triangle PQR has vertices P(3, −6), Q(0, 9), and R(−3, 0). Triangle P'Q'R' has vertices P'(1, −2), Q'(0, 3), and R'(−1, 0). Plot triangles PQR and P'Q'R' on your own coordinate … 
Math
Find the perimeter of a regular 360sided polygon that is inscribed in a circle of radius 5 inches. If someone did not remember the formula for the circumference of a circle, how could that person use a calculator’s trigonometric …