Calculus (pleas help!!!)
posted by Cady .
Find the absolute maximum and absolute minimum values of the function
f(x)=(x−2)(x−5)^3+11 on each of the indicated intervals.
Enter 1000 for any absolute extrema that does not exist.
(A) Interval = [1,4]
Absolute maximum =
Absolute minimum =
(B) Interval = [1,8] .
Absolute maximum =
Absolute minimum =
(C) Interval = [4,9] .
Absolute maximum =
Absolute minimum =
My answers are:
(A) Interval = [1,4]
Absolute maximum = 9
Absolute minimum = 5
(B) Interval = [1,8] .
Absolute maximum = 173
Absolute minimum = 5
(C) Interval = [4,9] .
Absolute maximum = 459
Absolute minimum = 1000
Only the max for the second one and the max for the third one are right.... I don't know what to do....

f'(x)=(x5)^3+(x2)3(x5)^2=(4x11)(x5)^2
(A) Absmax=f(1)=64+11=75
Absmin=f(11/4)=3^7/2^8+11=2187/256+
+11=629/256
(B) Absmax=f(8)=173
Absmin=f(11/4)=629/256
(C) Absmax=f(9)=459
Absmin=f(4)=9
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