how would you solve....
15x + 50 + x to the second power....
15x+50+x =16x+50
(15x+50+x)^2=(16x+50)^2
(16x+50)^2=(16x)^2+2*16x*50+50^2=
16^2*x^2+1600x+2500=
256x^2+1600x+2500
i need help but i cant use a calculater becuz that has no to the second power ans x or any letters
To solve the expression 15x + 50 + x^2, follow these steps:
1. Combine like terms: The given expression contains two terms with the variable x, which are 15x and x^2. Add them together to simplify.
15x + x^2 + 50
2. Rearrange the terms: It is common practice to write polynomial expressions in descending order of their exponents. So, rearrange the expression by moving the term with the highest exponent (x^2) to the front.
x^2 + 15x + 50
Now you have the given expression simplified and rearranged.
At this point, it seems like you want to solve the equation rather than simplify the expression. To solve the equation x^2 + 15x + 50 = 0, you can apply the quadratic formula or attempt to factor it. However, it's worth noting that this equation does not factor easily, so the quadratic formula would be a suitable approach.
Quadratic formula:
For an equation in the form ax^2 + bx + c = 0, the quadratic formula states that x = (-b ± √(b^2 - 4ac)) / (2a).
For our equation, a = 1, b = 15, and c = 50. Plugging these values into the quadratic formula, we get:
x = (-15 ± √(15^2 - 4(1)(50))) / (2(1))
Simplifying further:
x = (-15 ± √(225 - 200)) / 2
x = (-15 ± √25) / 2
Now we have two potential solutions:
x = (-15 + 5) / 2 = -5/2 = -2.5
x = (-15 - 5) / 2 = -20/2 = -10
Therefore, the solutions to the equation x^2 + 15x + 50 = 0 are x = -2.5 and x = -10.