You look up and see a helicopter pass directly overhead: 3.10-s later you hear the sound of the engines. If the air temperature is 23.0°C, How high was the helicopter flying?

Question

You look up and see a helicopter pass directly overhead: 3.10-s later you hear the sound of the engines. If the air temperature is 23.0°C, How high was the helicopter flying?

Answer 1

d=distance v=velocity t=time

d = vt

331+0.6 (23) = 354.6

354.6 * 3.10 = 1068.88m

Answer 2

Well, that's quite the high-flying dilemma! Let's see if we can figure it out.

First, we need to know that the speed of sound in air depends on the temperature. At 23.0°C, the speed of sound is approximately 343 meters per second.

Since you heard the sound 3.10 seconds after seeing the helicopter, we can calculate how far the sound traveled during that time. By multiplying the speed of sound (343 m/s) by the time (3.10 s), we'll find the distance the sound waves covered.

So, 343 m/s * 3.10 s equals about 1,063.3 meters.

Since the sound reached you, it means that the helicopter must have been at least 1,063.3 meters high when you saw it.

But hey, don't forget that sound can also travel horizontally. So, the helicopter could have been even higher up!

So, as for the exact height of the helicopter, I can't say for sure. However, it was at least 1,063.3 meters up in the air. That's pretty high, isn't it?

Answer 3

To determine the height of the helicopter, we can use the speed of sound and the time it took for the sound to reach you. The speed of sound in air depends on the air temperature. The general equation to calculate the distance traveled by sound is:

distance = speed × time

First, let's calculate the speed of sound at 23.0°C. The speed of sound in dry air can be approximated using the following formula:

speed of sound (in m/s) = 331.5 + (0.6 × temperature in Celsius)

Using the given air temperature of 23.0°C, we can calculate the speed of sound:

speed of sound = 331.5 + (0.6 × 23.0)
= 331.5 + 13.8
= 345.3 m/s

Now, we can calculate the distance traveled by the sound using the time delay of 3.10 seconds:

distance = speed × time
distance = 345.3 × 3.10
distance ≈ 1070.43 meters

Therefore, the helicopter was flying at a height of approximately 1070.43 meters.

Answer 4

height=velocitysound*time

so figure the velocity of sound at 23C