What is the molality of a solution in which 15g of I2 is dissolved in 500g of alcohol?
is that I for iodine?
YES
Please type your subject in the School Subject box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.
To find the molality of a solution, you need to know the amount of solute (in moles) and the mass of the solvent (in kilograms). Here's how you can calculate the molality of the given solution:
1. Convert the mass of I2 from grams to moles:
To do this, you need to know the molar mass of I2. The molar mass is the sum of the atomic masses of each element in the compound. For I2, the molar mass is 2 x 126.9 g/mol = 253.8 g/mol.
Number of moles of I2 = Mass of I2 / Molar mass of I2
= 15 g / 253.8 g/mol
2. Convert the mass of the alcohol from grams to kilograms:
Given that the mass of the alcohol is 500g, the mass in kilograms is 500g / 1000g/kg = 0.5 kg.
3. Calculate molality:
Molality (m) = Moles of solute / Mass of solvent (in kg)
= moles of I2 / mass of alcohol
Now, putting all the values together:
Molality (m) = (15 g / 253.8 g/mol) / 0.5 kg
Simplify the expression:
Molality (m) = 0.059 mol / 0.5 kg
Divide the numerator by the denominator:
Molality (m) = 0.118 mol/kg
Therefore, the molality of the solution in which 15g of I2 is dissolved in 500g of alcohol is 0.118 mol/kg.