24ml of .05 mol per litre of SILVRE NITRATE reacts with 15 ml of potassium chloride.calculate molar concentration of potassium chloride.
Technically the problem is flawed and the answer can't be calculated; however, I assume you mean that the KCl reacts COMPLETELY and stoichiometrically with the AgNO3.
AgNO3 + KCl ==> AgCl + KNO3
moles AgNO3 = M x L = ??
Using the coefficients in the balanced equation, convert moles AgNO3 to moles KCl (it is 1:1).
Now M KCl = moles KCl/L KCl.
0.337
To calculate the molar concentration of potassium chloride, we need to first determine the number of moles of silver nitrate that reacted with the potassium chloride.
1. Calculate the number of moles of silver nitrate:
- Given: Volume of silver nitrate solution = 24 mL
- Given: Concentration of silver nitrate = 0.05 mol/L
- Moles of silver nitrate = Concentration * Volume
= 0.05 mol/L * 0.024 L
= 0.0012 mol
2. Determine the number of moles of potassium chloride:
- Given: Volume of potassium chloride solution = 15 mL
- We don't know the concentration of potassium chloride yet, so let's denote it as 'C' (in mol/L).
- Moles of potassium chloride = Concentration * Volume
= C * 0.015 L
= 0.015C mol
3. Equate the moles of silver nitrate and potassium chloride since they react in a 1:1 ratio (according to the balanced chemical equation):
- 0.0012 mol (silver nitrate) = 0.015C mol (potassium chloride)
4. Solve for the concentration of potassium chloride:
- 0.015C mol = 0.0012 mol
- C = 0.0012 mol / 0.015
- C ≈ 0.08 mol/L
Therefore, the molar concentration of potassium chloride is approximately 0.08 mol/L.