find the vertex, the line of symmetry, the max or min value of f(x)=2x^2-8x+16
h = Xv = -b/2a = 8/4 = 2.
Substitute 2 for X in the given Eq:
K = Yv = 2*2^2 - 8*2 + 16 = 8.
V(h,k) = V(2,8).
Line of symm = h = 2.
Ymin = Yv = K = 8.
Substitute 2 for X in the given Eq:
K = Yv = 2*2^2 - 8*2 + 16 = 8.
V(h,k) = V(2,8).
Line of symm = h = 2.
Ymin = Yv = K = 8.