What is the Keq of NaOBr dissolving in water if the Ka of HOBr dissociating is 6.4*10^-6

Keq = Kb = Kw/Ka

65,8,d,9

To determine the Keq for the dissolution of NaOBr in water, we first need to understand the relationship between Keq and Ka.

Keq (the equilibrium constant) is the ratio of products to reactants quantitatively at equilibrium for a chemical reaction. On the other hand, Ka (the acid dissociation constant) is specifically used for acid-base reactions and measures the extent of acid dissociation.

In this case, the dissociation of HOBr can be represented by the following equation:

HOBr ⇌ H+ + OBr-

The Ka value of 6.4 x 10^-6 can be expressed as:

Ka = [H+][OBr-]/[HOBr]

To find the Keq value for the dissolution of NaOBr in water, we need to determine the stoichiometry of the reaction. Assuming NaOBr dissociates completely, the equation for the reaction can be written as:

NaOBr → Na+ + OBr-

Since NaOBr is a salt and does not contain any H+ ions, it does not directly contribute to the equilibrium expression. Therefore, the Keq for the reaction can be written as:

Keq = [OBr-]

In this case, Keq is equal to the concentration of OBr- at equilibrium because there are no other species present in the reaction that would contribute to the equilibrium expression.

However, to calculate the concentration of OBr- at equilibrium, we need additional information such as the initial concentration or other equilibrium conditions. Please provide more details or any additional information if available, so that I can help you determine the Keq value for the dissolution of NaOBr in water.