Two redtangles are similar. One has a length of 11 cm and a width of 6 cm, and the other has a width of 5 cm. Find the length of the second rectangle. Round to the nearest tenth if necessary.

Please type your subject in the School Subject box. Any other words, including obscure abbreviations, are likely to delay responses from a teacher who knows that subject well.

"Similar" shapes keep the same ratio of side lengths, although the sizes may be different. One is a magnified version of the other.

The Length/Width ratio of each rectangle is the same

In your case, 11/6 = x/5

Solve for the unknown length x, and round to nearest one-tenth cm.

To find the length of the second rectangle, we can use the concept of similarity. Similar figures have corresponding sides that are proportional. In this case, the width of one rectangle is 6cm, and the width of the other rectangle is 5cm.

To find the length of the second rectangle, we can set up a proportion using the corresponding sides. Let's use "x" to represent the length of the second rectangle.

6 cm / 11 cm = 5 cm / x

Cross-multiplying, we get:

6 cm * x = 11 cm * 5 cm

Simplifying, we have:

6x = 55 cm^2

To solve for x, we divide both sides of the equation by 6:

x = 55 cm^2 / 6

Calculating, we find:

x ≈ 9.17 cm

Therefore, the length of the second rectangle is approximately 9.17 cm when rounded to the nearest tenth.