if ED=10 and DB=3x-8 whats the lenght of EB
There are in fact three cases.
Case 1: (seemingly obvious case)
E-----D--------B
ED=10
DB=3x-8
EB=10+3x-8=3x+2
Case 2:
E-----B-------D
ED=10
DB=3x-8
EB=10-(3x-8)=18-3x=3(6-x)
Case 3:
D-----E--------B
ED=10
DB=3x-8
EB=3x-8 - 10 = 3x-18=3(x-6)
To find the length of EB, we need to use the given information about ED and DB.
Given that ED = 10 and DB = 3x - 8, we can find EB by subtracting the length of DB from the length of ED.
EB = ED - DB
Substituting the given values, we can write the equation as:
EB = 10 - (3x - 8)
Next, let's simplify the equation:
EB = 10 - 3x + 8
EB = -3x + 18
So, the length of EB is -3x + 18.