Two hundred liters of gas at zero degrees Celsius are kept under a pressure of 150 kPa. The temperature of the gas is raised to 273 degrees Celsius and the pressure is increased to 600 kPa. What is the new volume?

P1V1/T1=P2V2/T2

solve for V2, change temps to kelvins

To find the new volume of the gas, we can use the combined gas law equation:

(P1 * V1) / T1 = (P2 * V2) / T2

where:
P1 is the initial pressure
V1 is the initial volume
T1 is the initial temperature
P2 is the final pressure
V2 is the final volume (which we need to find)
T2 is the final temperature

Let's plug in the given values:
P1 = 150 kPa
V1 = 200 liters
T1 = 0 degrees Celsius + 273 = 273 Kelvin
P2 = 600 kPa
T2 = 273 degrees Celsius + 273 = 546 Kelvin

Now let's solve for V2:
(150 kPa * 200 liters) / 273 K = (600 kPa * V2) / 546 K

Simplifying the equation:
(150 * 200) / 273 = (600 * V2) / 546

Now, multiply both sides of the equation by 273 * 546 to isolate V2:
150 * 200 * 546 = 600 * V2 * 273

Divide both sides by 600 * 273:
150 * 200 * 546 / (600 * 273) = V2

After calculating this expression, we find that V2 is approximately 132.61 liters.

Therefore, the new volume of the gas is approximately 132.61 liters when the temperature is raised to 273 degrees Celsius and the pressure is increased to 600 kPa.