A small bottle of propane gas (C3H8) contains 400.0 grams of propane. When the propane is burned in oxygen, how many moles of each product are formed?

first write the balanced chemical equation:

C3H8 + 5O2 -> 3CO2 + 4H2O
**note: in combustion reaction of organic compounds, the usual products are carbon dioxide and water.
then calculate for molecular weight of propane (the C3H8),, Carbon is 12 while H is 1:
3*12 + 8*1 = 44 g/mol
since initially we have 400 g of propane, we divide this by the molecular weight to get the number of moles of propane:
400 g / 44 g/mol = 9.09 mol C3H8
now we can use this to get the number of moles of each product (the CO2 and H2O) formed:
for CO2 : 9.09 mol C3H8 * 3 mol CO2 / 1 mol C3H8 = 27.27 mol CO2
for H2O : 9.09 mol C3H8 * 4 mol H2O / 1 mol CO2 = 36.36 mol H2O

hope this helps~ :)

To find out the number of moles of each product formed when propane (C3H8) is burned in oxygen, we first need to write the balanced chemical equation for the combustion reaction:

C3H8 + 5O2 → 3CO2 + 4H2O

From the balanced equation, we can see that for every 1 mole of C3H8, 3 moles of CO2 (carbon dioxide) and 4 moles of H2O (water) are formed.

To calculate the number of moles of propane, we need to determine the molar mass of propane (C3H8):

1 mole of carbon (C) has a molar mass of 12.01 g/mol
3 moles of carbon (C) × 12.01 g/mol = 36.03 g/mol
8 moles of hydrogen (H) × 1.008 g/mol = 8.064 g/mol

Total molar mass of propane (C3H8) = 36.03 g/mol + 8.064 g/mol = 44.094 g/mol

Now, let's calculate the number of moles of propane gas (C3H8) using the given mass of 400.0 grams:

Number of moles = Mass / Molar mass
Number of moles of propane = 400.0 g / 44.094 g/mol ≈ 9.07 moles

Therefore, when 400.0 grams of propane gas (C3H8) is burned in oxygen, it will produce approximately:
- 9.07 moles of CO2
- 12.09 moles of H2O

To determine the number of moles of each product formed when propane (C3H8) is burned in oxygen (O2), we need to balance the equation for the combustion reaction first.

The balanced equation for the combustion of propane is:

C3H8 + 5O2 -> 3CO2 + 4H2O

From the balanced equation, we can see that for every mole of propane (C3H8) that reacts, we get 3 moles of carbon dioxide (CO2) and 4 moles of water (H2O) as products.

Now, let's calculate the number of moles of propane (C3H8) from the given mass of 400.0 grams. To do this, we need to know the molar mass of propane, which can be obtained from the periodic table.

The molar mass of carbon (C) is approximately 12.01 g/mol, and the molar mass of hydrogen (H) is approximately 1.01 g/mol. Since propane (C3H8) contains 3 carbon atoms and 8 hydrogen atoms, we can calculate its molar mass as follows:

Molar mass of C3H8 = (3 * Molar mass of C) + (8 * Molar mass of H)
= (3 * 12.01 g/mol) + (8 * 1.01 g/mol)
= 36.03 g/mol + 8.08 g/mol
= 44.11 g/mol

Now, we can calculate the number of moles of propane using the given mass:

Number of moles = Mass of substance / Molar mass
= 400.0 g / 44.11 g/mol
≈ 9.07 moles

Since the balanced equation shows that for every 1 mole of propane, we get 3 moles of carbon dioxide and 4 moles of water, we can multiply the number of moles of propane by the stoichiometric coefficients to get the number of moles of each product:

Number of moles of CO2 = 9.07 moles * 3
≈ 27.21 moles

Number of moles of H2O = 9.07 moles * 4
≈ 36.28 moles

Therefore, when 400.0 grams of propane is burned in oxygen, approximately 27.21 moles of carbon dioxide and 36.28 moles of water are formed.