Find Molecular and net ionic equation for
Al(NO3)3 + Na2CO3
Hint: aluminum carbonate is not soluble.
To find the molecular and net ionic equations for the reaction between Al(NO3)3 and Na2CO3, we will break down the process step by step.
Step 1: Determine the chemical formula for each reactant.
Al(NO3)3 is aluminum nitrate.
Na2CO3 is sodium carbonate.
Step 2: Write the balanced molecular equation by combining the reactant formulas and balancing the chemical equation.
Al(NO3)3 + 3Na2CO3 → Al(CO3)3 + 6NaNO3
Step 3: Identify the soluble and insoluble compounds.
In this reaction, all compounds are soluble, meaning they dissociate completely in water.
Step 4: Write the complete ionic equation by separating the soluble compounds into their constituent ions.
Al(NO3)3 (aq) + 3Na2CO3 (aq) → Al(CO3)3 (aq) + 6NaNO3 (aq)
Step 5: Determine the spectator ions, which are ions that are present before and after the reaction but do not actively participate.
In this reaction, Na+ and NO3- ions are spectators.
Step 6: Write the net ionic equation by removing the spectator ions.
Al(NO3)3 (aq) + 3Na2CO3 (aq) → Al(CO3)3 (s) + 6NaNO3 (aq)
Now you have the molecular equation: Al(NO3)3 + 3Na2CO3 → Al(CO3)3 + 6NaNO3 and the net ionic equation: Al(NO3)3 + 3Na2CO3 → Al(CO3)3 + 6NaNO3.