trig
posted by Sushmitha .
use an inverse trig function to write è as a function of x
(There is a right triangle.
The hypotenuse is 2.
è is the angle between the base and the hypotenuse.
The base/adjacent side of è is (x + 1)
The side opposite è does not have a value.)
a) è = sqrt [4  (x + 1)^2] all divided by 2
b)è = cos ^ 1 [(x + 1)/2]
c)è = tan ^ 1 [(x + 1)/2]
d)è = sin ^ 1 [2/(x + 1)]
How do I do this? I'm leaning towards B, the inverse cosine because only the adjacent side and hypotenuse are given. The opposite side is not given, and there is already a variable x in the given adjacent side.
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