The complete combusion of 0.5763 grams of glucose in a bomb calorimeter (Cbomb = 6.20 kJ/degrees C) raises the temperature of the calorimeter by 1.45 degrees C. what is the food value of glucose in calories per gram? (Hint: remember 1 Cal = 4.184 kJ)
i do not know how to find the calories per gram, help?
calories=mass(L) where L is calories/gram for glucose.
HEAT=Cbomb*1.45=mass*L
L=1.45*cbomb/mass
To find the food value of glucose in calories per gram, we need to convert the energy released in the combustion of glucose from kJ to calories and then divide it by the mass of glucose.
First, we need to calculate the energy released in the combustion of glucose. We can use the formula:
Energy released = mass of glucose * heat capacity of the bomb calorimeter * temperature rise
Given:
- Mass of glucose = 0.5763 grams
- Heat capacity of the bomb calorimeter (Cbomb) = 6.20 kJ/°C
- Temperature rise = 1.45 °C
Energy released = 0.5763 grams * 6.20 kJ/°C * 1.45 °C
Next, we convert the energy released from kJ to calories. We know that 1 Calorie (with a capital 'C') is equivalent to 4.184 kJ.
So, energy released (in Calories) = Energy released (in kJ) / 4.184
Finally, we divide the energy value in Calories by the mass of glucose to get the food value of glucose in calories per gram.
Food value of glucose (in calories per gram) = Energy released (in Calories) / mass of glucose
By following this process, you can find the food value of glucose in calories per gram.