If 3.00 mol of calcium carbonate is heated to produce calcium oxide and carbon dioxide, how many grams of carbon dioxide gas are produced?
answered above.
To find the mass of carbon dioxide gas produced, we need to use the molar mass of carbon dioxide (CO2) and the given amount of calcium carbonate.
The balanced equation for the reaction is:
CaCO3(s) → CaO(s) + CO2(g)
From the equation, we can see that 1 mol of calcium carbonate produces 1 mol of carbon dioxide.
To find the molar mass of carbon dioxide, we need to add up the atomic masses of carbon (C) and two oxygen atoms (O).
Molar mass of carbon dioxide (CO2):
(12.01 g/mol for C) + (2 * 16.00 g/mol for O) = 44.01 g/mol
Now, we have all the information we need to calculate the mass of carbon dioxide gas produced:
Mass of carbon dioxide (g) = Number of moles of carbon dioxide (mol) * Molar mass of carbon dioxide (g/mol)
Given:
Number of moles of calcium carbonate = 3.00 mol
Number of moles of carbon dioxide = Number of moles of calcium carbonate = 3.00 mol
Molar mass of carbon dioxide = 44.01 g/mol
Mass of carbon dioxide produced (g) = 3.00 mol * 44.01 g/mol
Simplifying the calculation:
Mass of carbon dioxide produced (g) = 132.03 g
Therefore, 132.03 grams of carbon dioxide gas are produced when 3.00 moles of calcium carbonate are heated.