given 90 ml of Hydrogen gas collected with the temperature is 27 degrees C. What
volume will the Hydrogen occupy at 42 C ?
assuming the Hydrogen gas is ideal, we can use the formula:
(V1)/(T1) = (V2)/(T2)
where
V1 = initial volume
T1 = initial temperature (units in Kelvin)
V2 = final volume
T2 = final temperature (units in Kelvin)
since the given temp are in degree Celsius, we first convert it to Kelvin by adding 273:
T1 = 27 + 273 = 300 K
T2 = 42 + 273 = 315 K
substituting to the formula:
90 / 300 = (V2) / 315
V2 = 94.5 mL
hope this helps~ :)
To solve this problem, we can use the Combined Gas Law, which relates the initial and final volumes of a gas with their corresponding temperatures:
(V1/T1) = (V2/T2)
where:
V1 is the initial volume of the gas (90 ml)
T1 is the initial temperature of the gas (27 degrees C or 300 K)
V2 is the final volume of the gas (unknown)
T2 is the final temperature of the gas (42 degrees C or 315 K)
Let's plug in the values into the equation and solve for V2:
(90 ml / 300 K) = (V2 / 315 K)
To find V2, we can cross multiply and then divide:
90 * 315 = 300 * V2
28350 = 300 * V2
To isolate V2, we divide both sides of the equation by 300:
V2 = 28350 / 300
V2 = 94.5 ml
Therefore, the volume of the hydrogen gas at 42 degrees C will be approximately 94.5 ml.
To solve this problem, we can use the combined gas law formula. The combined gas law relates the initial and final volumes, temperatures, and pressures of a gas.
The formula for the combined gas law is as follows:
(P1 * V1) / (T1) = (P2 * V2) / (T2)
Where:
P1 and P2 are the initial and final pressures of the gas.
V1 and V2 are the initial and final volumes of the gas.
T1 and T2 are the initial and final temperatures of the gas.
In this case, we are given the initial volume V1 as 90 mL, the initial temperature T1 as 27 degrees Celsius, and we need to find the final volume V2 at a temperature of 42 degrees Celsius.
Now, first, let's convert the temperatures from Celsius to Kelvin, as the gas laws use Kelvin temperature scale.
To convert Celsius to Kelvin, we use the formula:
Kelvin = Celsius + 273.15
So, let's convert the temperatures:
Initial temperature T1 = 27 + 273.15 = 300.15 K
Final temperature T2 = 42 + 273.15 = 315.15 K
Now, we can plug these values into the combined gas law formula and solve for V2:
(P1 * V1) / T1 = (P2 * V2) / T2
Since the question does not provide information about pressure, we can assume that the pressure remains constant. Therefore, the pressure term can be canceled out.
So, the equation becomes:
V1 / T1 = V2 / T2
Now, substitute the given values:
90 mL / 300.15 K = V2 / 315.15 K
To find V2, rearrange the equation:
V2 = (90 mL / 300.15 K) * 315.15 K
Simplifying the equation:
V2 ≈ 94.45 mL
Therefore, at a temperature of 42 degrees Celsius, the volume of the hydrogen gas will be approximately 94.45 mL.