How to prepare 1000 nM stock solution using Tam (1 gm) Mol Weight=563.6
To prepare a 1000 nM (nanomolar) stock solution using Tam (1 gm) with a molecular weight of 563.6, you need to follow these steps:
1. Calculate the number of moles of Tam in 1 gram:
Number of moles = Mass / Molecular weight
Number of moles = 1 gm / 563.6 g/mol
2. Convert the desired concentration from nanomolar to molar:
1 nM = 1 x 10^-9 M (molar)
3. Calculate the volume of the stock solution needed to achieve the desired concentration:
Volume (in liters) = Number of moles / Concentration (in M)
Volume (in liters) = (Number of moles / 1 x 10^-9 M)
4. Convert the volume to milliliters (ml) for ease of measurement:
Volume (in ml) = Volume (in liters) x 1000
Now, let's do the calculations:
1. Number of moles = 1 gm / 563.6 g/mol = 0.001776 moles
2. Concentration = 1000 nM = 1000 x 10^-9 M = 1 x 10^-6 M
3. Volume (in liters) = 0.001776 moles / 1 x 10^-6 M = 0.001776 liters
4. Volume (in ml) = 0.001776 liters x 1000 = 1.776 ml
Therefore, to prepare a 1000 nM stock solution using 1 gram of Tam (with a molecular weight of 563.6), you need to dissolve the Tam in approximately 1.776 ml of solvent (typically water or an appropriate buffer).