While standing on a horizontal frictionless surface, a 50 kg student pushes against a wall with an average force of 125 N east for 0.110 s. Calculate the velocity of this student at 0.110 s
To calculate the velocity of the student at 0.110 s, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by the acceleration it experiences:
Force = Mass * Acceleration
We know the force exerted by the student (125 N) and the mass of the student (50 kg), so we can rearrange the equation to solve for acceleration:
Acceleration = Force / Mass
Acceleration = 125 N / 50 kg
Acceleration = 2.5 m/s²
Now, we can use the equation for velocity to find the student's velocity at 0.110 s:
Velocity = Initial Velocity + (Acceleration * Time)
Since the student was initially at rest, the initial velocity is 0 m/s. Plugging in the values we have:
Velocity = (0 m/s) + (2.5 m/s² * 0.110 s)
Velocity = 0 m/s + 0.275 m/s
Thus, the velocity of the student at 0.110 s is 0.275 m/s (east).