algebra
posted by Anonymous .
Theresa has $26 in her wallet. The bills are worth either $5 or $1. If there are 14 bills total, how many does she have of each type?

Set up your given:
Let x be $5
Let y be $1
Amount: 5x + y = 26
Number of bills: x + y = 14
Solve the equations by elimination:
(multiply the first equation by 1 to make y negative.. it would then cancel out)
5x  y = 26
x + y = 14
4x = 12
x = 3
Plug in x to any of your orig. equations
x + y = 14
$5 = 3
$1 = 143
= 11
Check: 3 $5 bills and 11 $1 bills equal to 14 bills.
Check: 3x$5 = $15
11x$1 = $11
$15 + $ 11 = $26 
Is it 3 fives and 11 ones
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