# algebra

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Theresa has \$26 in her wallet. The bills are worth either \$5 or \$1. If there are 14 bills total, how many does she have of each type?

• algebra -

Let x be \$5
Let y be \$1
Amount: 5x + y = 26
Number of bills: x + y = 14

Solve the equations by elimination:
(multiply the first equation by -1 to make y negative.. it would then cancel out)
-5x - y = -26
x + y = 14
-4x = -12
x = 3

Plug in x to any of your orig. equations
x + y = 14
\$5 = 3
\$1 = 14-3
= 11

Check: 3 \$5 bills and 11 \$1 bills equal to 14 bills.
Check: 3x\$5 = \$15
11x\$1 = \$11
\$15 + \$ 11 = \$26

• algebra -

Is it 3 fives and 11 ones

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