what is the probability of selecting 5 from 90 numbers if these were selected first and had been added to it again 13-60-6-24-72
The probability of selecting any 5 form 90 numbers is
1/C(90,5) = 1/(43949268)
or about 1 in 44 million
I don't understand what the fact that certain numbers have been selected but then returned, have anything to do with the stated outcome.